ACR Anchor Method?
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jktinst wrote: In a lead fall + hanging belayer + blown-leg test, sure, it makes sense that with the belayer's weight clipped directly to the anchor's central point, you'd get a higher load multiplication than if it was tethered through a dynamic tether. Basically, this makes the case for always tethering with a dynamic tether, be it the rope, a Béal dynaconnexion, a Petzl Connect, a length of dynamic rope with a Kong Slyde, etc. (which is what I do and which has been discussed elsewhere on this thread). I also still feel that it confuses the issue to use as your reference point for load multiplication in a blown-leg scenario the simple static weight of the hanging belayer. From what I understand, Ioad multiplication as a result of anchor extension usually means the multiplication factor between the fall getting arrested on the full/intact anchor and the same fall arrested with one anchor leg blowing. Talking about worst case scenarios: how about comparing a quad, a cordelette and a statically-equalized dynamic rope anchor (à la rgold) on a 2-leg anchor with legs of significantly different lengths and a 5kN fuse on each leg (with the anchor pre-equalized for a straight-down load, not pre-equalized in a direction other than down)? We're not talking about manufacturing gizmos that may fail or be misused here. Just having useful information to help understand in what circumstances some types of anchors might be safer than others. Finally, the main reason I started posting on this thread (despite determinedly abstaining from it when it first started) is because I am still trying to understand why your load distribution results (no blown leg) for the simple two-leg sliding X are different from the DAV's. Several years back, you reported a 1:3.7 distribution ratio for the sliding X pre-equalized in a direction other than down and tested on a drop tower with the weight on a track, which I found mind-bogglingly uneven. Could it have been a typo? On this thread, your numbers are more reasonable: 1:1.7 or 1:1.9, depending on the post, and you're also reporting (for the first time, as far as I know) a comparison between different equalization testing methods. With the DAV tests, from what I can see without understanding German, it seems that they got a 1:1.3 distribution when the weight mimicking the leader was dropped from 3m up and 1m to the left of the sliding X's central point (edited to add: again, with the weight mimicking the belayer hanging statically from the anchor) . Any discussion of the possible reasons for the differences would be most welcome. So would details of the 4 different methods you compared for the two-leg sliding X. PS: I think I've seen your "3-leg sliding X" referred to as a "sliding W" before. Has anyone else? The reasons for not testing with dynamic elements added into the belayer/belay system is that a) this is not worst case, b) there is no universal standard for the dynamic element c) the objective is to test belay system effectiveness, not dynamic elements which may or may not be included in the system. |
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The link formatting here seems to chop off the rockclimbing.com URL so I don't think that the active link to the precise page would work. |
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jktinst wrote:The link formatting here seems to chop off the rockclimbing.com URL so I don't think that the active link to the precise page would work. The post I was referring to is on p.2 of The Lab forum. Thread title: Stupid Simple Elette (last post on thread: Nov. 10, 2011). Regarding the DAV climbing wall drop tests, with the weight mimicking the belayer hanging from the anchor's central point and the one mimicking the leader falling from 1m off to the side, I don't see how it can be claimed that their pre-equalizing the anchor skewed their results towards a more even distribution. I understand that having dynamic elements in the system (dynamic rope and tether, swinging and bouncing of the leader weight, etc.) introduces more parameters that are difficult to manage and standardize but I would think that the main point of this exercise is to have tests that are as representative as possible of real-life situations and, in that respect, it seems to me that those DAV tests are very representative. By comparison, drop tower tests where you manually pre-equalize the anchor in a direction other than that of the weight's vertical track to force the anchor to equalize while aligning with the track under load do not seem as representative to me. It's as if the leader fell on the anchor in a direction other than down. Or, to be a bit more realistic, it's as if the leader fell from precisely above the anchor's mid-point (ie the lowest possible position that the central point can reach) while the belayer, anticipating this fall, jumped or swung himself off to the side to get out of the way, thereby pre-equalizing the anchor in a direction other than straight down. Not impossible but not a particularly typical scenario either. That part of that thread was discussing Neoshades bizarre claim that the setup on the right-hand side of the photo below, ".... a handy little truly-self-equalizing leg on a cordalette (or equalette in this case). :- I´m not so suprised I got such poor load sharing, that idea suffers from the same problems as the Alpine Equaliser in that to move the cord has to slide through ALL the karabiners (or in his case karabiner and coats hooks). |
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Copied from RC.com: |
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jktinst wrote: Regarding the DAV climbing wall drop tests, with the weight mimicking the belayer hanging from the anchor's central point and the one mimicking the leader falling from 1m off to the side, I don't see how it can be claimed that their pre-equalizing the anchor skewed their results towards a more even distribution. It's because the master point is already set in the "ideal" position (or close to it). Where as in many situations the biner will have to move to this location. This doesn't happen instantly, nor does it occur before load is applied. |
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Yes the belayer weight held the central point at its lowest position, which would have been ideal to obtain an even distribution if the leader weight had dropped in the same alignment. With the leader weight dropped 1m to the side of this alignment, the initial impact of the fall pulled the central point towards that side. Then the leader's weight would have swung towards the other side (but by then the load will already be quite a bit lower), etc. If anything, it seems to me that the belayer's weight, by resisting the pull of the central point to one side then the other, would have made the sliding X anchor behave more like a static one, with less equalization, or am I completely misreading what happens in this kind of situation? If I got that more or less right, then isn't it also possible that the inertia of the belayer weight could have evened out the load distribution for the static cordelette-type anchor, yielding a more even distribution in this situation than it might have if the belayer weight wasn't hanging from the anchor? |
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jktinst wrote:I thought that it was pretty clear that these numbers were for your standard two-leg anchor testing of three different basic set-ups: single strand (as in a quad clipped in a single strand), standard sliding X and "funny 8". This 1:3.7 figure for the sliding X seems to have been obtained with 6mm cord. Your more recent 1:1.7 / 1:1.9 figures were with 8mm? And the DAV tests were with some sort of sewn webbing slings but I don't think I ever worked out exactly which kind. Well the guy understood! |
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Brian L. wrote: It's because the master point is already set in the "ideal" position (or close to it). Where as in many situations the biner will have to move to this location. This doesn't happen instantly, nor does it occur before load is applied. The time the load is applied is usually faster than the reaction time of the anchor, so the peak load is seen before the master point biner can achieve the ideal location, and thus the load distribution is more offset than expected. I believe the explanation for this is due to friction in the system. Lower friction systems, like say a quad - with no twist around the master point biner - will be better than higher friction systems like the ACR, sliding X - which have a twist - but they wont be perfect. The number of sliding elements also impacts this, and I expect the anchor material does as well. With an offset drop test AND some belayer weight there is never enough sideways force applied to move the central karabiner, the force required to move the karabiner is less than that required to pull the falling weight sideways. You can work out the force required from the karabiner factor of the central point for any given material and karabiner wrap from the measured load split, for example the horizontal force required to move a weighted central karabiner in a sliding X and 8mm cord is 38% of the belayer weight. Once the central weight is approx 1/3rd the falling weight nothing moves. |
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Jim Titt wrote: With an offset drop test AND some belayer weight there is never enough sideways force applied to move the central karabiner, the force required to move the karabiner is less than that required to pull the falling weight sideways. You can work out the force required from the karabiner factor of the central point for any given material and karabiner wrap from the measured load split, for example the horizontal force required to move a weighted central karabiner in a sliding X and 8mm cord is 38% of the belayer weight. Once the central weight is approx 1/3rd the falling weight nothing moves. I actually measured the vertical and horizontal forces involved and the horizontal was only 28% of the vertical so not suprisingly nothing happened. Right, that makes perfect sense. My explaining was in the case on an unweighted belay - which i think was the condition of som of the testing reported in this thread (not the DAV article). |
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Right, I´ll put the graphs up for an offset drop test on an unweighted belay in the morning, it´s midnight here! |
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Jim Titt wrote: Well the guy understood!... You mean Neoshade understood that you had tested his various 3-arm systems? Maybe he did but I didn't see any clear indication of that in his subsequent posts. Jim Titt wrote: I said the three karabiner system as in his diagram... Wow! I really did not understand this to mean a test of the entire 3-arm system. A standard two-arm sliding X requires 3 biners; the Central biner on the photo was on a standard sliding X; this photo (3-pro "stacked binary" system yielding a theoretical distribution of 1:1:2) showed only 2 biners but if you replaced the coathooks by biners, it would have 5; and your results in "1:x" format were clearly indicative of two-arm systems. jktinst wrote:...now you can put this into your diagrams and work out the loadings you get in reality... ...As if the numbers were for various standard two-arm components and he would need to use these numbers to work out how his 3-arm systems distribute the load. Jim Titt wrote: With an offset drop test AND some belayer weight there is never enough sideways force applied to move the central karabiner, the force required to move the karabiner is less than that required to pull the falling weight sideways... Is quite interesting too. |
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The discussion was ONLY regarding the central and right hand points and the system used to link them, the rest of the anchor was anyway not worth wasting time on. Clearly the anchor is not "equalising" and the person positioning the karabiner is pre-disposing the forces on each piece. |
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Have any of the tests of sliding vs. non-sliding systems looked purely at equalization based on unequal arm lengths? |
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You really only have to look at work like Marc Beverly´s on multi-piece fixed anchors and compare with the results for whatever sliding system you are interested in. Obviously the moment the stretch in the longer leg(s) put´s a higher load split on the pieces than the sliding system gives then the dynamic system will move to maintain that load split. |
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I've seen a lot of different test results for multipiece fixed anchors, and see how unequal arm lengths reduce equalization. Do Beverley's tests come to different conclusions? I only see his work on ice screws and abalakovs. |
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paulraphael wrote:I've seen a lot of different test results for multipiece fixed anchors, and see how unequal arm lengths reduce equalization. Do Beverley's tests come to different conclusions? I only see his work on ice screws and abalakovs. What i don't see is tests that specifically address unequal arm lengths with on-axis loads in a sliding anchor (x, acr, alpine equalizer etc.). I'd be curious to know if the system is able to compensate for the different length "springs" of the arms, or if the system binds under load and acts like a fixed system. I understand that extending pieces with high-modulus materials can reduce the effect of unequal arm length. In practice I find this kind of rigging slow and tedious, and don't think very many people will actually do it. Especially on long routes, alpine terrain, etc. Doubt anyone has bothered to test it because the answer is fairly obvious, the longer leg will stretch more until the load split exceeds whatever the system gives and then start to slide so in that sense a dynamic system compenates for unequal lenghts but only to the limits inherent in the system. So for example the ACR will always give 28% of the load on the longer leg and 72% on the shorter in a two-piece anchor. This implies the longer leg must be over three times longer than the shorter one. |
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Sorry to bring this one back again... I'm not much of a scientist type but I'm curious to see the load distribution numbers on the eyeballed cordalette(non self equalizing) with an offset load. I read the whole thread and didn't seem to see it, maybe I missed it. It seems like, no matter what, if you offset the load on a knotted cordalette you must be dividing the load 100%, 0%, 0% with the piece opposite the fall direction getting all of the load. So while it seems like we've agreed that self equalization doesn't work as well in practice as it does in theory at least it does to some degree divide that offset load. Maybe I'm just completely overlooking something, thoughts? |
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Jack Mullen wrote:Sorry to bring this one back again... I'm not much of a scientist type but I'm curious to see the load distribution numbers on the eyeballed cordalette(non self equalizing) with an offset load. I read the whole thread and didn't seem to see it, maybe I missed it. It seems like, no matter what, if you offset the load on a knotted cordalette you must be dividing the load 100%, 0%, 0% with the piece opposite the fall direction getting all of the load. So while it seems like we've agreed that self equalization doesn't work as well in practice as it does in theory at least it does to some degree divide that offset load. Maybe I'm just completely overlooking something, thoughts? Jim has posted on this previously at rc.com back in 2011. Here's what he had to say: |
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Good man, someone has been paying attention!!!! |
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Haha, yeah I saw those posts and thought it was really interesting data, so copied it into Notepad. |






