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fall factor equation?

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By Monty
Mar 10, 2007
Me on a wonderfully hard problem... mmmm crimpers

I was wondering if anyone knew the equation to figure out what factor those big whippers are?

By Kevin Stricker
From Evergreen, CO
Mar 10, 2007
Noah's first rope...kinda.

length of fall / length of rope out. 2 is the highest you can get ( falling twice as far as you have rope out) and that only happens on a multipitch route where you fall past your belayer without protection.

By Lee Smith
Mar 10, 2007
You can love your rope but you can't "LOVE" your rope

Kevin is correct with the basic formula for a fall factor, but there are many variables that affect the forces on a rope, a belayer and the climber not to mention the anchor that is taking the most force--usually the top anchor.

One of the best discussions of forces during falls is in Craig Connally's excellent book, "The Mountaineering Handbook". He has a whole chapter on climbing forces that is a must read.

There are certain situations where a fall factor can be more than 2. Top rope self belay is one of them. When the TR anchor is approached, the rope out can be mere inches. Carry on past the anchor (slings on a bolt for example) and a fall of several feet can load a few inches of rope. Very bad!

By Charles Dalgleish
From Salt Lake City, Utah
Mar 10, 2007
Flakes of Wrath in Moab Utah.

Lee Smith wrote:
There are certain situations where a fall factor can be more than 2. Top rope self belay is one of them. When the TR anchor is approached, the rope out can be mere inches. Carry on past the anchor (slings on a bolt for example) and a fall of several feet can load a few inches of rope. Very bad!

Quick question? How can you climb several feet with no rope out? Not trying to be a smart ass, but by definition, a factor 2 is as high as it goes based solely on rope out and climber position. Yes, you can add in factors like the belayer jumping away and such, but the basic system limits at 2 FMU.

And slings factor into rope length too.

So if you have a sling that hangs 3 feet below the anchor, and you fall from the anchor, you are in fact falling 6 feet on 3 feet or more of rope, thus close to factor 2. If you climb 10 feet above the anchor, it's now 16" on 13" of rope. Well, you get the idea...

By Lee Smith
Mar 10, 2007
You can love your rope but you can't "LOVE" your rope

Slings are not dynamic and do NOT factor into rope length.

Here is the scenario:

Top rope solo. You have some device that slides up the rope but locks if you fall. The rope is tied off to the upper anchor. The anchor is 2 shoulder length slings on 2 bolt anchors in the typical way. As you approach the bottom of the slings, your rope clamp comes very close (say 3 inches) to the knot at the bottom of the slings. If you fall you have only this dynamic rope, no more. You can keep climbing as far as you can extend the slings (@ 18 inches). Now if you fall you can go 3 feet on a 3 inches of dynamic rope. That is a fall factor of 12. Granted, the total force generated would be on the low side in this fall, but it is still a bad scenario since you would static load the anchor and a very small length of dynamic rope.

I have top rope solo'ed for years and often encountered this very scenario. At some point in time someone showed me the error of my ways, and I now avoid this by either 1) not climbing above the anchor sling's lowest point or 2) leaving slack between the anchor and my rope grab device.

It is also a very good idea to back up a TR solo.

By Mark Nelson
From Coniferous, CO
Mar 10, 2007
 In a zoo in California, a mother tiger gave birth to a rare set of triplet tiger cubs.    Unfortunately, due to complications in the pregnancy, the cubs were born prematurely and due to their tiny size, they died shortly after birth. <br /><br />The mother tiger after recovering from the delivery, suddenly started to decline in health, although physically she was fine. The veterinarians felt that the loss of her litter had caused the tigress to fall into a depression. The doctors decided that if the tigress could surrogate another mother's cubs, perhaps she would improve. <br /><br />After checking with many other zoos across the country, the depressing news was that there were no tiger cubs of the right age to introduce to the mourning  mother. The veterinarians decided to try something that had never been  tried in a zoo environment. Sometimes a mother of one species will take on the care of a different species. The only "orphans" that could be found quickly, were a litter of weaner pigs.  The zoo keepers and vets wrapped the piglets in tiger skin and placed the babies around the mother tiger.<br />

I see that situation (fall factor relating to top rope soloing) as more of a whiplash to the climber than impacting 2 equalized bolts or 2 equalized active trad placements to the point of destructive failure. Granted there is very very little dynamic absorption provided by the rope, but the only way I see anchor failure is using two crappy button heads slung using the ADT as the anchor.

(assume my equalization proposed uses a good angle between pieces; typically, I use either a limited extension sliding X or a cordalette/webalette -- I back up sometimes with static line, but never have failed the cord or a sliding X).

For a practical example, look at an aid climb lead where the climber neglects to clip the rope into the preceding placement and only has a daisy or other sling into the lower placement. The climber progresses to a higher placement which blows out and the climber loads the preceding piece with more than an 18" x2 fall, usually it's about 2'-3' x2, this equates to enough to force to snap the climber, but not really enough impact to blow apart a bomber piece rated about 10kN, I've seen 8kN hold a static impact about 4' fall distance overall, no problem.

While the fall factor may be mathematically increasing by formula in the top rope soloing, the impact force & duration is just not enough to fail an equalized anchor with 2 good placements. Certainly not 2 equalized 3/8" bolts in highly cemented rock.

One thing that is beneficial to the anchor in the top rope solo fall that generates moderate impact force & low duration is not introducing the pulley effect to the anchor. With this also, I don't see spring force playing a role, nor do I see the pendulum problem.

So is this "bad"? - yea, to the climber, their day is pretty much finished & might need to see a doc and get scanned to see if anything other than soft tissue was damaged.

But, my .02 is that the equalized anchor using good angles between pieces is not going anywhere.

By Charles Dalgleish
From Salt Lake City, Utah
Mar 11, 2007
Flakes of Wrath in Moab Utah.

Lee Smith wrote:
Slings are not dynamic and do NOT factor into rope length. Here is the scenario: Top rope solo. You have some device that slides up the rope but locks if you fall. The rope is tied off to the upper anchor. The anchor is 2 shoulder length slings on 2 bolt anchors in the typical way. As you approach the bottom of the slings, your rope clamp comes very close (say 3 inches) to the knot at the bottom of the slings. If you fall you have only this dynamic rope, no more. You can keep climbing as far as you can extend the slings (@ 18 inches). Now if you fall you can go 3 feet on a 3 inches of dynamic rope. That is a fall factor of 12. Granted, the total force generated would be on the low side in this fall, but it is still a bad scenario since you would static load the anchor and a very small length of dynamic rope. I have top rope solo'ed for years and often encountered this very scenario. At some point in time someone showed me the error of my ways, and I now avoid this by either 1) not climbing above the anchor sling's lowest point or 2) leaving slack between the anchor and my rope grab device. It is also a very good idea to back up a TR solo.

Not true. Checking any available equation used for fall factors we get the given information:
1-distance fallen/rope out=FF
2-FF cannot be greater than 2.

By it's very definition.

So, you are talking about forces, not fall factors. Forces can certainly peak (as pointed out by you, and me earlier), but in reference to fall factors, 2 is the biggest you can go.

If a climber takes a fall while he is simul climbing, and his partner has 10 feet of slack, and falls at the same time, what is the fall factor? Distance of fall/rope out. Is there other factors that are effecting the rope and the anchors and belays, yup, but the fall factor is still as defined.

By Kevin Stricker
From Evergreen, CO
Mar 11, 2007
Noah's first rope...kinda.

You guys are soo funny....Has no one taken an aid fall onto their daisy before? I have and guess what I am still here...no snapped spine or anything. Also...nylon does stretch, so do static ropes.

BTW Lee, the trick for increasing safety when Top rope soloing is to use the rope to make your anchor ( bunny ears knot works wonders) Then nothing in your setup is static. I almost never use slings when soloing as the rope works better in most cases.

By Lee Smith
Mar 11, 2007
You can love your rope but you can't "LOVE" your rope

Kevin,

You are 100% right--we are soo funny. We're FUNNY but not FUN-AY if you know what I mean.

You're also right about using the rope as the anchor set-up when top rope soloing.

I still believe it is not good to take any length fall on static slings, daisies, whatever. It is also not good to load up a short piece of dynamic rope. Simple things to keep one alive.

I will cite Craig Connally's book again and in his expert opinion, you can have fall factors above 2, such as my scenario and in the via ferrata world.

By Monty
Mar 11, 2007
Me on a wonderfully hard problem... mmmm crimpers

thanks a lot for all your guys input

By Charles Dalgleish
From Salt Lake City, Utah
Mar 11, 2007
Flakes of Wrath in Moab Utah.

Lee Smith wrote:
I still believe it is not good to take any length fall on static slings, daisies, whatever. It is also not good to load up a short piece of dynamic rope. Simple things to keep one alive.

agreed whole heartedly. One of my most painful learning mistakes was top rope self belay will bouldering a wall. I used a long piece of webbing to keep me from decking, but then proceeded to take a 2' fall onto it. Racked my back, nuts, and waist. Would have been better to have decked than that experience. Fall factor on it was 2' fall/6' sling=.33, but considering how little stretch tube webbing has, ouch.

"I will cite Craig Connally's book again and in his expert opinion, you can have fall factors above 2, such as my scenario and in the via ferrata world."



I will cite Beal, BD, climbing mag, rock and ice, beta.com, this site, FotH, and various others that all state unequivacably that there is no such thing as fall factors being greater than 2. Again, craig may have gotten mixed up with the notion of fall forces, but fall force is not = to a fall factor.

Not really worth flogging the horse more.

By brenta
From Boulder, CO
Mar 11, 2007
Cima Margherita and Cima Tosa in the Dolomiti di Brenta.  October 1977.

Charles Dalgleish wrote:
I will cite Beal, BD, climbing mag, rock and ice, beta.com, this site, FotH, and various others that all state unequivacably that there is no such thing as fall factors being greater than 2.

How do you define the "rope paid out" in the via ferrata scenario?
I don't think FotH or the Beal site--the two I've checked from your list--provide unequivocal support to your claim. FotH refers to "length of rope fallen on," which is not necessarily the rope paid out. The video on the Beal site defines the fall factor as "hauteur de chute / longueur de corde utile." The Handbook of Mountaineering on Ice and Mixed Terrain of the Italian Alpine club defines the fall factor as the ratio of length of fall to length or rope involved. It cites the via ferrata scenario as a case in which the fall factor may exceed 2.
In normal roped climbing, fall factors do not exceed 2, but think of the following (admittedly unlikely) example. A climber takes a long fall, from 10 meters above the belay and with no intermediate pro. As he goes by his belayer, the rope gets snagged behind a flake so that only two meters are available to absorb energy. What is the fall factor? According to your definition, it's 1.2, but that definition makes the fall factor irrelevant in understanding the dynamics of that fall. If you measure the rope that stops the fall, the factor is 6, which tells you it's a very serious fall.

By Lee Smith
Mar 11, 2007
You can love your rope but you can't "LOVE" your rope

Thanks Brent. That is exactly what I was talking about.

By Charles Dalgleish
From Salt Lake City, Utah
Mar 11, 2007
Flakes of Wrath in Moab Utah.

How do you define the "rope paid out" in the via ferrata scenario? I personally don.t, seeing as to me, it's not climbing. That's akin to calling a boat ride swimming, or riding an airplane flying (to all those parachuters out there, you know what I'm saying. If you really consider this CLIMBING, power to ya mate, but by that definition, I took a nearly infinite fall factor when I fell out of bed this morning with no rope (limit as rope->0). See where that goes?


"I don't think FotH or the Beal site--the two I've checked from your list--provide unequivocal support to your claim. FotH refers to "length of rope fallen on," which is not necessarily the rope paid out. The video on the Beal site defines the fall factor as "hauteur de chute / longueur de corde utile."

except the part on the beal site that says very clearly that in "Its value, lying between 0 and 2 in climbing conditions, is ...." Pretty black and white. check here http://www.bealplanet.com/portail-2006/index.php?page=facteu>>>>>


"In normal roped climbing, fall factors do not exceed 2, but think of the following (admittedly unlikely) example. A climber takes a long fall, from 10 meters above the belay and with no intermediate pro. As he goes by his belayer, the rope gets snagged behind a flake so that only two meters are available to absorb energy. What is the fall factor? According to your definition, it's 1.2, but that definition makes the fall factor irrelevant in understanding the dynamics of that fall. If you measure the rope that stops the fall, the factor is 6, which tells you it's a very serious fall."

Again, checking the beal site, and many others, you'll find that the fall factor has nothing to really do with anything. It's a notion of something. It tells us a little about a particular instance, but it leaves out way too much info to be used in any meaningful way. Check the link above. Or google it, you'll find over 50 sites that all confirm the same thing.

Mind you, wikipedia does mention that fallfactors can be higher than 2 in via ferreta, but not climbing. Is this what you are getting at? If so, that's fine. How about a 1" fall above your anchors, that's a factor 2 fall mate, and you'd be pretty hard pressed to hurt yourself with that (if your harness and the "boys" are situated properly). How about if I'm 2" above, and as I fall, my partner sucks in the rope, meaning nearly an infinitely high fall factor based on your notion. Still equates to a 2" fall to me. If you really want, we could crunch out the whole m=Fa, and all that for your forces. Lord knows I can get more forces by taking a 5 footer at a fall factor of 1.

That's why I thought the horse could lay down. If you really want, there's plenty of sites out there that you can use to account for ALL forces affecting you in a fall, and not a one will resort to fall factor in any meaningful way, if even using it in a passing mention.

Sorry to come across like this, kinda my personality, kinda a long day of work, and kinda already been answered. No ill will intended, and if we ever cross paths we could try to measure the pull of gravity/atmospheric pressure of beer entering our gullet/belly.

and lastly sorry about the quotes, not used to the forums mechanics yet.

By brenta
From Boulder, CO
Mar 11, 2007
Cima Margherita and Cima Tosa in the Dolomiti di Brenta.  October 1977.

Charles, I disagree. Not on the beer part towards the end, but on three main counts.

1. Many reputable sources give a definition of fall factor that has the length of rope involved in stopping the fall at the denominator. Even more sources are ambiguous. The Beal site is one of the ambiguous one, or contradictory if you prefer.

2. The fall factor is a useful concept. Climbers should be familiar with it. Obviously, it refers to an idealized situation, does not help much in the analysis of short falls, and so on, but, as you and I and many others know, it reminds us that dw = F(x)dx.

3. Definitions are to some extent arbitrary. However, in practice, there are better definitions and worse definitions. A better definition for fall factor is one that allows one to apply the concept to a wider range of situations.

Oh, and if you take that limit for rope->0, you get the fall factor for a rope of zero length, not for no rope. Ask yourself "How long is my non-rope?" After that, maybe, it's time for a beer...

By Mark Nelson
From Coniferous, CO
Mar 11, 2007
 In a zoo in California, a mother tiger gave birth to a rare set of triplet tiger cubs.    Unfortunately, due to complications in the pregnancy, the cubs were born prematurely and due to their tiny size, they died shortly after birth. <br /><br />The mother tiger after recovering from the delivery, suddenly started to decline in health, although physically she was fine. The veterinarians felt that the loss of her litter had caused the tigress to fall into a depression. The doctors decided that if the tigress could surrogate another mother's cubs, perhaps she would improve. <br /><br />After checking with many other zoos across the country, the depressing news was that there were no tiger cubs of the right age to introduce to the mourning  mother. The veterinarians decided to try something that had never been  tried in a zoo environment. Sometimes a mother of one species will take on the care of a different species. The only "orphans" that could be found quickly, were a litter of weaner pigs.  The zoo keepers and vets wrapped the piglets in tiger skin and placed the babies around the mother tiger.<br />

Kevin Stricker wrote:
Has no one taken an aid fall onto their daisy before? I have and guess what I am still here...no snapped spine or anything.


Yea, I'm no-one to assess injury like a whiplash. So, if climber injury occurs on average at 12kN and we have falls that are held by 6-8kN nuts (or whatever placement type) on the daisy or other sling; then yea, the certainty of injury is in question -- A static catch just impacts the climber more than the dyanmic rope, I think that's pretty fair to say.

Sorry about that, I get really analytical with anchors & gear and overthink other aspects.

My bro & I have both taken 4 footers on dyneema. It did hurt like a mother, but we weren't calling for a litter evac by any means. Though it did teach us to get better balance with our feet and hips when aiding and clip the rope in for the main catch.

By Tango76
Feb 12, 2008


2-FF cannot be greater than 2. By it's very definition.

Ok, I'm a climbing nobody and I'm sure most people here have tons of experience more than I do... but here's how a guide explained fall factors higher than 2 to me:

Fall factor can theoretically be infinite. It gets higher than 2 if the belayer recovers some slack as the leader falls directly on the belay. If you manage to do this (I don't know why you would do it...) then the rope you fall on can be significantly less than half the fall, thus generating a fall factor higher than 2, and theoretically infinite (if you just recover ALL the rope as the leader falls).

Does this make any sense?

By George Bell
From Boulder, CO
Feb 12, 2008
Hip trouble ...

Tango76 wrote:
Does this make any sense?


Not much. How much rope do you think the belayer can pull in during the ~3 seconds it takes the leader to fall 50m? Not enough to make any significant difference in the fall factor. If unanchored, the belayer could run away or jump off, but notice that this does not shorten the rope between belayer and leader so it reduces the fall factor, since the leader will have a shorter fall.

In a gym or any situation where the climber can't fall past the belayer, you can't have a fall factor greater than 1. Any fall longer than this the climber is going to hit the ground, and not be stopped by the rope!

It IS possible to get fall factors beyond 2 in situations that do not involve leading. For example, in "Via Ferrata" climbers are soloing with a runner clipped to a fixed cable, which is anchored every once in a while. If you fall, you zip down the cable to be stopped by the next anchor, generating huge forces and fall factors on the runner.

By Hbar
Feb 12, 2008

Reading through the posts above, it seems to me that it may be helpful if the fall factor is derived here, with some of its idealizations spelled out. There are several, but I believe that in the vast majority of typical falls, it captures very important dynamics. On the scale of physics problems, it is quite easy, but I apologize in advance to those who don't think in this way. Just skip to the next post.

A systematic way to approach this is through conservation of energy. The kinetic energy acquired by a falling climber is w*d, where w is the weight of the climber, and d is the distance fallen until the rope starts to catch (idealization number 1). The rope has a maximum ability to absorb energy proportional to the length made available to absorb energy (i.e. stretch), mathematically, E(absorbed by rope)=A*l, where A is a constant dependant on the rope, and l is the amount of rope out (idealization number 2, there is, for example, some energy absorption potential in the anchors, and belayer, etc.). To absorb all of the kinetic energy, we have the identity w*d-A*l=0 (for now, because of a desire for simplicity, I am ignoring the fact that A is not always going to be at its maximum value. I introduce this variation below). If the equation is not equal to 0, then that is energy absorbed by the climber.

Rearranging, we have, for safe climbing, w*d (less than) A*l, with the less than arising from the fact that A is for maximum absorption of energy, and ropes are designed to not, in general, need all of that, or to use all of that capacity to absorb energy. Since w and A are fixed by the climber and the rope, we want to rearrange the equation above to see how things change for different falls for a given team. Simple rearrangement gives w/A (less than) d/l. The right hand side of this equation is what we are getting at with the fall factor. The idea is that this inequality, which is a necessary (but not sufficient, for those who care) condition for safe climbing is hardest to satisfy when d/l is large. d/l is the fall factor. As seen from above, it measures how much we are flirting with reversing the inequality above and therefor having to absorb the excess energy by breaking bones, or anchors and then bones. Remember that there is a lot of uncertainty in the values on the left hand side of the equation.

The fall factor does not mean much when falls are extremely short (inches as noted above, for example), because the energy (w*d) that must be absorbed by other systems like the belayer, climber and anchor is so small. Also, energy absorption is in most cases a separate issue from the stress loading on the anchor. An anchor can take an enormous stress and not absorb a meaningful amount of energy. The rope snag example can be well captured by the fall factor as derived above, and does, in fact give a large fall factor.

I hope this helps more people than it confuses!

By brenta
From Boulder, CO
Feb 12, 2008
Cima Margherita and Cima Tosa in the Dolomiti di Brenta.  October 1977.

Hbar wrote:
The kinetic energy acquired by a falling climber is w*d, where w is the weight of the climber, and d is the distance fallen until the rope starts to catch (idealization number 1).

Reasoning in terms of kinetic energy is not a good idea. Better to think in terms of potential energy. That allows you to easily account for the fact that the total energy to be absorbed by the rope is not w*d, but w*(d+s), where s is the amount of stretch of the rope. If you equate that energy to the energy stored in the rope when the climber reaches the lowest point, (ks^2/2l), you get the impact force equation shown here.

By Hbar
Feb 12, 2008

brenta wrote:
Reasoning in terms of kinetic energy is not a good idea. Better to think in terms of potential energy. That allows you to easily account for the fact that the total energy to be absorbed by the rope is not w*d, but w*(d+s), where s is the amount of stretch of the rope. If you equate that energy to the energy stored in the rope when the climber reaches the lowest point, (ks^2/2l), you get the impact force equation shown here.


If you want to extend the calculation or relate it to manufacturers specifications simply, including s is a better choice as you pointed out. However, if you are only interested in the things I was addressing above, including s simply amounts to a rescaling of A. My choice of A works exactly because s is proportional to l. What the additional factors do is simply reduce the value of the parameter A as defined in your approach to the value of A in my approach. Since A is empirical, this is unimportant, provided you don't confuse the different definitions. To be strictly correct, I would need to write A(w), since a change in w can change the effective value of A. However, A is fixed for each climber anyway (less importantly, the dependence on changing w is relatively weak), so I decided not to include that dependence for clarity. A drawback of such a calculation is that you can't naively associate the value of A for a given climber with manufacturing specs for a climbing rope.

I quite like the Beal link you attached. Should be fun to spend a bit more time with it while it is winter and climbing is curtailed for me.

By Tango76
Feb 12, 2008

George Bell wrote:
Not much. How much rope do you think the belayer can pull in during the ~3 seconds it takes the leader to fall 50m? Not enough to make any significant difference in the fall factor. If unanchored, the belayer could run away or jump off, but notice that this does not shorten the rope between belayer and leader so it reduces the fall factor, since the leader will have a shorter fall. In a gym or any situation where the climber can't fall past the belayer, you can't have a fall factor greater than 1. Any fall longer than this the climber is going to hit the ground, and not be stopped by the rope! It IS possible to get fall factors beyond 2 in situations that do not involve leading. For example, in "Via Ferrata" climbers are soloing with a runner clipped to a fixed cable, which is anchored every once in a while. If you fall, you zip down the cable to be stopped by the next anchor, generating huge forces and fall factors on the runner.


Well, as I wrote that was just the explanation I received when I asked a mountain guide how was theoretically possible to generate fall factors higher than 2. Theoretically being the key word, because as you said there's no practical reason to do such a thing.

But if you manage to pull 50cms of rope (basically one arm-length slack)with the leader 5 meters above the belay, you'd generate a 2.11 fall factor. Grated, you'd have no reason to do such a thing... but theoretically fall factors higher than 2 appear to be possible under this scenario. He also told me something about possible scenarios during simul-climbing if the second falls right before a leader's fall, when theoretically you could generate very high fall factors, but it was a long time ago and I cannot remember how exactly this was...

I started climbing in the Dolomites where Via Ferrata routes are very common, and I remember a lot of people telling me most people underestimated the risks of that setup, and at the time I couldn't understand why. Now that I understand dynamic ropes and how fall factor works, I recognize you can generate really huge factors with that rig. People usually use full body harnesses and a dynamic break now to "smoothen" a fall, but still I would be interested in reading some study of the consequences of a long fall during a via ferrata, considering a lot of people climbing them are tourists with no climbing training and little understanding of the risks...

By sactownclimber
From Sacramento, CA
Feb 12, 2008
Me on the summit of Mt. Whitney. That's Mt. Russel in the background.

For those interested in a thorough treatment of this, click here
and open the attached pdf.

By George Bell
From Boulder, CO
Feb 12, 2008
Hip trouble ...

Tango76 wrote:
... if you manage to pull 50cms of rope (basically one arm-length slack)with the leader 5 meters above the belay, you'd generate a 2.11 fall factor. Granted, you'd have no reason to do such a thing... but theoretically fall factors higher than 2 appear to be possible under this scenario.


I suppose so, but 2.11 is a long way from infinity! If you are the belayer in such a situation (short fall right onto a hanging belay) you should not pull in any slack. It is not ones natural impulse, however.

Tango76 wrote:
He also told me something about possible scenarios during simul-climbing if the second falls right before a leader's fall, when theoretically you could generate very high fall factors, but it was a long time ago and I cannot remember how exactly this was...


If two climbers are simulclimbing, and the leader hasn't put any gear in for the past 20m, imagine what happens when the SECOND falls. He pulls the leader off and they fall together. After 20m, the leader comes to the anchor, and the length of the rope stopping the fall is very short, so the fall factor can be large. Of course the rope isn't tied to the anchor, but only going over it, so it's more complex than a normal belay. I've never heard of a rope breaking by this mechanism, but this is a big hazard of simulclimbing, which is why experts advise having the better climber go second.

By brenta
From Boulder, CO
Feb 12, 2008
Cima Margherita and Cima Tosa in the Dolomiti di Brenta.  October 1977.

Hbar wrote:
However, if you are only interested in the things I was addressing above, including s simply amounts to a rescaling of A. My choice of A works exactly because s is proportional to l.

Allow me to be a bit pedantic here. If s were proportional to l for fixed w, the impact force, which is just k*s/l, would be independent of the fall factor.

I believe I understand your main idea: The higher the fall, the more energy is at play. The more rope is involved, the easier it will be to absorb that energy.

An ideal spring stores energy by stretching. Of course, the more it stretches, the higher the forces on the climber and the anchors. The way ropes are built nowadays, forces that hurt a climber or damage an anchor are usually well below the rope's tensile strength. So, what matters is the maximum force that a climber or an anchor may withstand.

Let this force be F and let k be the force required to double the length of a piece of rope. Then A = F^2/2k. Let f be the fall factor. If we omit s from the left hand-side of the equation, we get f < A/w. If we include it, we get f < A/w - F/k. So, the effect of accounting for s is additive rather than multiplicative, and A does not depend on w, but otherwise I concur with your analysis.

By brenta
From Boulder, CO
Feb 12, 2008
Cima Margherita and Cima Tosa in the Dolomiti di Brenta.  October 1977.

George Bell wrote:
If two climbers are simulclimbing, and the leader hasn't put any gear in for the past 20m, imagine what happens when the SECOND falls. He pulls the leader off and they fall together. After 20m, the leader comes to the anchor, and the length of the rope stopping the fall is very short, so the fall factor can be large. Of course the rope isn't tied to the anchor, but only going over it, so it's more complex than a normal belay.

In the situation you describe, assuming both climbers have mass m, you can still apply the impact force equation, but with the fall factor defined by twice the height of the leader over the last piece of pro divided by the length of rope between leader and second. This ratio is at most two. Hence, the effective fall factor is less than or equal to two. This analysis, however, disregards friction at the anchor: This is a more egregious omission in this case than in the standard belay case.

[Note: the derivation is based on the following energy balance equation: mg(2h+s) = ks^2/2l, which is the same equation used for the impact force calculation except for the factor of 2 in front of h.]


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